我的题目是：用链栈实现将十进制数转化为八进制数，我编完了，可我不会改啊，都改了无数个日夜了，还是改不好。有哪位好心的人能帮帮我啊？将不胜感激啊！。程序就在下面，帮帮忙，救救我吧，交不上程序我就挂了啊。呜呜呜呜呜
#include<stdio.h>
#include<math.h>
struct node
{
int data;
struct node *next;
}LinkStack;
void init_stack(struct node *top)
{
top->data='-1';
top->next=NULL;
}
int decide_empty(struct node  *top)
{
if(top->data=='-1')
return (1);
else
return (0);
}
void Enter_stack(struct *top,int x)
{  ;
 top=(LinkStack*)malloc(sizeof(LinkStack));
 top->data=x;
 top->next=top;
printf("\nOK!\n");
return(top);
}
int del_stack(struct *top)
{
if(top==NULL)
 {
  printf("\n栈为空!");
 }
 else
 {
top=top->next;
  free(top);
 }
}

main()
{
stacklist L;
int n,e;
L=init_stack(struct node *top);
printf("please input a decimal number:");
scanf("%d,&n");
if(n<=0)
printf("error due to the wrong input!\n");
while(n）
{
Enter_stack( L ,n%8);
n=n/8;
}
printf("the changed number is:\n");
while(decide_empty(L))
{
e=del_stack(L);
printf("%d",e);
}

}

[[it] 本帖最后由 zitong1987611 于 2008-4-19 11:57 编辑 [/it]]

我的题目是：用链栈实现将十进制数转化为八进制数，我编完了，可我不会改啊，都改了无数个日夜了，还是改不好。有哪位好心的人能帮帮我啊？将不胜感激！会把我所有的分都给你。程序就在下面，帮帮忙，救救我吧，交不上程序我就挂了啊。呜呜呜呜呜
#include<stdio.h>
#include<math.h>
struct node
{
int data;
struct node *next;
}LinkStack;
void init_stack(struct node *top)
{
top->data='-1';
top->next=NULL;
}
int decide_empty(struct node  *top)
{
if(top->data=='-1')
return (1);
else
return (0);
}
void Enter_stack(struct *top,int x)
{  ;
 top=(LinkStack*)malloc(sizeof(LinkStack));
 top->data=x;
 top->next=top;
printf("\nOK!\n");
return(top);
}
int del_stack(struct *top)
{
if(top==NULL)
 {
  printf("\n栈为空!");
 }
 else
 {
top=top->next;
  free(top);
 }
}

main()
{
stacklist L;
int n,e;
L=init_stack(struct node *top);
printf("please input a decimal number:");
scanf("%d,&n");
if(n<=0)
printf("error due to the wrong input!\n");
while(n）
{
Enter_stack( L ,n%8);
n=n/8;
}
printf("the changed number is:\n");
while(decide_empty(L))
{
e=del_stack(L);
printf("%d",e);
}

}