猜数字小游戏简单源代码 - C语言论坛

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猜数字小游戏简单源代码

猜数字小游戏简单源代码，闲着无聊写的菜代码，很垃圾
也是纯粹练习一下手工高亮代码而已

// header file
#include<stdio.h>
#include<stdlib.h>
#include<time.h>

// define var-type
typedef const char* PCSTR;
typedef PCSTR const CPCSTR;

// define read-only variables
#define ERROR_INPUT 0x80000000
CPCSTR INFO_ERROR = "对不起，您输入的数字不对，请重新输入：";
CPCSTR INFO_SPLIT = "******************************************************";
CPCSTR INFO_INPUT = "请您输入一个数字：";
CPCSTR INFO_GAME = "您好，现在请您猜一个1000以内的整数。\n您有%d次机会，每次您猜错了，系统会提\n示您猜得大了或者小了。祝您玩得愉快！\n";
CPCSTR INFO_FAIL = "您好，您的次数已到！";
CPCSTR INFO_QUIT = "请问您还想继续玩吗？是请按1：";
CPCSTR INFO_TIMES= "这是您第%d次猜数，结果是";
PCSTR INFO_GUESS[3] = {
    "您输入的数字太小，请继续猜。",
    "您猜对了！恭喜！",
    "您输入的数字过大，请继续猜。",
};

// get the sign of the integer
int sgn(int n)
{
    if(n==0) return 0;
    else return n>0?1:-1;
}

// input a integer
int InfoGetInt(PCSTR str)
{
    int n;
    puts(str);
    if (scanf("%d", &n)==1) return n;
    else
    {
        while(getchar()!='\n');
        return ERROR_INPUT;
    }
}

// game start function,
// int _nChance : how many chances to guess
int GameStart(int _nChance)
{
    int nNum = rand() % 1000 + 1;
    int n = 1, nChance = _nChance;
    for ( ; n && nChance>0; --nChance) // loop while nChance>0
    {
        n = InfoGetInt(INFO_INPUT);
        while (n<1 || n>1000) // check input
        {
            n = InfoGetInt(INFO_ERROR);
        }
        n = sgn(n-nNum);
        printf(INFO_TIMES, _nChance - nChance + 1);
        puts(INFO_GUESS[n+1]);
    }
    return nChance;
}

// main function
int main(void)
{
    int nChance = 20;
    // output infomation about the game
    printf(INFO_GAME, nChance);
    puts(INFO_SPLIT);
    srand(time(NULL)); // randomize
    do // loop input test
    {
        if (GameStart(nChance) == 0) puts(INFO_FAIL);
        puts(INFO_SPLIT);
        // is exit program
    }while(InfoGetInt(INFO_QUIT)==1);
    return 0; // must be null
}

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[[it] 本帖最后由雨中飞燕于 2008-2-4 03:30 编辑 [/it]]