[此贴子已经被作者于2007-10-29 22:50:12编辑过]

#include<stdio.h>
#include<math.h>
void main()
{
void method(int k);
scanf("%d",&k) ;
void method(k);
}
void method(int k)
{
int k;
for(int x=0;x<sqrt(k);x++)
for(int y=0;y<sqrt(k);y++){
if((x*x+y*y)=1989)
printf("A root of equation is%d,%d\n",x,y);
}

或许，先计算1989的根更好。

void method(int k)
{

int root = sqrt(1989) + 1;

for ( int x = 0; x < root; x++ )
for ( int y = 0; y < root; y++ )
if ( (x*x + y*y) == 1989 )
cout << "x = " << x << " y = " << y << endl;
}