求求大佬解答，数组输入10个正整数，统计重复数字的个数，并输出重复数字和重复次数

#include <stdio.h>

// 数在 nums 中时，返回下标，否则返回 -1
int data_in_nums(int num, int *array, int tail)
{
    for (int i = 0; i < tail; i++)
    {
        if (num == array[i])
        {
            return i;
        }
    }
    return -1;
}

int main()
{
    int data[] = {1, 60, 55, 60, 24, 88, 75, 60, 48, 55};
    // int data[] = {74, 92, 70, 71, 33, 28, 32, 22, 9, 11};

    int nums[10] = {0};
    int tail = 0;
    int counts[10] = {0};

    for (int i = 0; i < 10; i++)
    {
        int j = data_in_nums(data[i], nums, tail);
        if (j != -1)
        {
            counts[j] += 1; // 已经存在的数，计数加一
        }
        else
        {
            int k = tail;
            nums[k] = data[i]; // 不存在的数，存入 nums
            counts[k] = 1;     // 计数置 1
            ++tail;
        }
    }

    if (tail == 10)
    {
        puts("NO");
        return 0;
    }
    for (int i = 0; i < tail; i++)
    {
        if (counts[i] > 1)
        {
            printf("%d: %d\n", nums[i], counts[i]);
        }
    }
}