[求助]用VB写自适应预测

这种我就直接上ChatGPT 3.5，让它给你回答了。

[求助]用VB写自适应预测
    用自适应算法根据福彩3D和值历史预测下次的和值置信区间，同时预测出和值的大小与奇偶，通过预测的大小、奇偶在预测的置信区间内挑选和值。
    先谢谢了！！！

以下是一个简单的VB代码示例，用于根据福彩3D历史数据预测下一次的和值置信区间和大小奇偶：
'定义历史数据数组
Dim historyData(999) As Integer
'读取历史数据
'...

'定义预测参数
Dim alpha As Double '学习速率
Dim beta As Double '遗忘因子
Dim n As Integer '预测步数
Dim m As Integer '自适应参数
Dim p As Integer '置信区间百分比

'初始化预测参数
alpha = 0.1
beta = 0.9
n = 1
m = 10
p = 90

'定义自适应预测函数
Function AdaptiveForecast(historyData() As Integer, alpha As Double, beta As Double, n As Integer, m As Integer, p As Integer) As Integer()
    '定义预测结果数组
    Dim forecastResult(n - 1) As Integer
    '定义自适应参数数组
    Dim adaptiveParameter(m - 1) As Double
    '初始化自适应参数数组
    For i = 0 To m - 1
        adaptiveParameter(i) = 1 / m
    Next
    '定义置信区间数组
    Dim confidenceInterval(1) As Integer
    '计算历史数据的平均值和标准差
    Dim mean As Double
    Dim stdDev As Double
    mean = Application.WorksheetFunction.Average(historyData)
    stdDev = Application.WorksheetFunction.StDev(historyData)
    '预测下一步的和值
    Dim forecastValue As Double
    forecastValue = mean
    For i = 0 To n - 1
        '更新自适应参数
        For j = 0 To m - 1
            adaptiveParameter(j) = (1 - alpha) * adaptiveParameter(j) + alpha * Abs(historyData(999 - i) - forecastValue) / stdDev
        Next
        '计算置信区间
        confidenceInterval(0) = Int(forecastValue - p / 100 * stdDev * Application.WorksheetFunction.NormSInv(1 - (1 - beta) / 2))
        confidenceInterval(1) = Int(forecastValue + p / 100 * stdDev * Application.WorksheetFunction.NormSInv(1 - (1 - beta) / 2))
        '更新预测结果
        forecastResult(i) = confidenceInterval(0) + Int(Rnd() * (confidenceInterval(1) - confidenceInterval(0) + 1))
        '更新预测值
        forecastValue = Application.WorksheetFunction.Average(forecastResult)
    Next
    '返回预测结果数组
    AdaptiveForecast = forecastResult
End Function

'调用自适应预测函数
Dim forecastResult() As Integer
forecastResult = AdaptiveForecast(historyData, alpha, beta, n, m, p)

'根据预测结果挑选和值
Dim selectedValue As Integer
Dim minValue As Integer
Dim maxValue As Integer
minValue = forecastResult(0)
maxValue = forecastResult(0)
For i = 0 To n - 1
    If forecastResult(i) < minValue Then
        minValue = forecastResult(i)
    End If
    If forecastResult(i) > maxValue Then
        maxValue = forecastResult(i)
    End If
Next
If (minValue + maxValue) Mod 2 = 0 Then '和值为偶数
    If minValue Mod 2 = 0 Then '最小值为偶数
        selectedValue = minValue
    Else '最小值为奇数
        selectedValue = maxValue
    End If
Else '和值为奇数
    If minValue Mod 2 = 0 Then '最小值为偶数
        selectedValue = maxValue
    Else '最小值为奇数
        selectedValue = minValue
    End If
End If

'输出预测结果和挑选的和值
MsgBox "预测结果：" & Join(forecastResult, ",") & vbCrLf & "挑选的和值：" & selectedValue

需要注意的是，这只是一个简单的示例代码，实际应用中需要根据具体情况进行调整和优化。