小白一枚，求助python3

hako 发布于 2019-08-05 13:56， 2344 次点击

我有一个字典，具体如下
{"message":"Success","result":[{"message":"Success","prediction":[{"label":"mark","probability":0.98014337},{"label":"jack","probability":0.019856641}],"file":"d.jpg"}]}

我想根据以上这个字典，判断“probability”大于0.9，所对应的“label”的指，上面这个例子结果应该返回“mark”

试了很多办法，一直不成功，，请各位前辈指教指教，多谢多谢

5 回复

wp2319572019-08-05 15:23

回复楼主 hako

>>> s={"message":"Success","result":[{"message":"Success","prediction":[{"label":"mark","probability":0.98014337},{"label":"jack","probability":0.019856641}],"file":"d.jpg"}]}
>>> for x in  s["result"][0]["prediction"]:
...   if x["probability"]>0.9:
...     print(x["label"])
...
mark
>>>

hako2019-08-05 16:53

回复 2楼 wp231957

感谢大神，我等会赶紧赶紧试试，跪谢大恩

hako2019-08-06 02:48

大神大神，谢谢很好建议，
谢谢各位前辈，按招指示已成功获取所需数据，很不幸，又出现了新问题
详情如下

d = json.loads(response.text)

for x in d["result"][0]["prediction"]:
if x["probability"]>0.8:
print(x["label"])
w = x["label"]
fi = "/var/lib/motion/" + w + ".wav"
print(fi)

执行后返回结果
mark
/var/lib/motion/jack.wav

为什么没有返回mark.wav,,
谢谢大家的帮忙

wp2319572019-08-06 10:37

回复 4楼 hako

>>> s={"message":"Success","result":[{"message":"Success","prediction":[{"label":"mark","probability":0.98014337},{"label":"jack","probability":0.019856641}],"file":"d.jpg"}]}
>>> for x in  s["result"][0]["prediction"]:
...    if x["probability"]>0.9:
...       w = x["label"]
...       break
...
>>> fi = "/var/lib/motion/" + w + ".wav"
>>> fi
'/var/lib/motion/mark.wav'
>>>

hako2019-08-06 12:41

感谢版主。威武。。。。。