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Python进程锁的下面两种用法为什么在Windows系统中执行结果不一样????急!!!

samsung0 发布于 2018-12-26 14:28, 1437 次点击
第一段代码
import multiprocessing
import time
lock = multiprocessing.Lock()
def fun():
    lock.acquire()
    for i in range(3):
        time.sleep(0.5)
        print(i)
    lock.release()
    return None
if __name__ == '__main__':
    p1 = multiprocessing.Process(target=fun, args=())
    p2 = multiprocessing.Process(target=fun, args=())
    p1.start()
    p2.start()
执行结果
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2
第二段代码
import multiprocessing
import time
lock = multiprocessing.Lock()
def fun(lock):
    lock.acquire()
    for i in range(3):
        time.sleep(0.5)
        print(i)
    lock.release()
    return None
if __name__ == '__main__':
    p1 = multiprocessing.Process(target=fun, args=(lock,))
    p2 = multiprocessing.Process(target=fun, args=(lock,))
    p1.start()
    p2.start()
第二段代码执行结果
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0
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2
1 回复
#2
wei_ai_lu2018-12-29 17:41
可以看下线程和进程的区别
1