python新手 t[1,1] = 1 / math.sqrt(4) 编译出现list indices must be integers or slices,

function dtt=dttmtx(N)
order_max = N;
for x=0:N-1
    t(1,x+1) = 1/sqrt(N);
end
for x=0:N-1
    t(2,x+1) = (2*x+1-N)*sqrt(3/(N*(N^2-1)));
end

for x=0:N-1
   for tt=2:order_max-1
       alpha1 = (2/tt)*sqrt((4*tt^2-1)/(N^2-tt^2));
       alpha2 = ((1-N)/tt)*sqrt((4*tt^2-1)/(N^2-tt^2));
       alpha3 = ((1-tt)/tt)*sqrt((2*tt+1)/(2*tt-3))*sqrt((N^2-(tt-1)^2)/(N^2-tt^2));
       t(tt+1,x+1) = (alpha1*x+alpha2)*t(tt-1+1,x+1)+alpha3*t(tt-2+1,x+1);
   end
end
dtt=t;

block_size =8;
k=dttmtx(block_size);
idx=1;

for i=1:block_size
    for j = 1: block_size
        kernel(:,:,idx)=k(i,:)' * k(:,j)';
        idx =idx+1;
    end
end


求用python实现这个matlab代码，这个代码主要就是求一个64个8*8的矩阵