关于汇编语言的dw

assume ds:datasg,cs:codesg,ss:stacksg
stacksg segment
    dw 0,0,0,0,0,0,0,0
stacksg ends

datasg segment
    db '1.display       '
    db '2.brows         '
    db '3.replace       '
    db '4.modify        '
    db '5.arrange       '
datasg ends

codesg segment
  start:mov ax,datasg
        mov ds,ax
        mov ax,stacksg
        mov ss,ax
        mov sp,10h
      

        mov bx,0
        mov cx,5
      s:push cx
        mov cx,4
        mov si,0
        y:mov al,[si+bx+2]
          and al,0dfh
          mov [si+bx+2],al
          inc si
          loop y
        pop cx
        add bx,10h
        loop s
      

        mov ax,4c00h
        int 21h
codesg ends
end start
end