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#2
mywisdom882016-10-19 17:34
if object_id('tempdb..#tb') is not null drop table #tb
go create table #tb(库位 varchar(5),件数 int,长 numeric(4,2),宽 numeric(4,2),高 numeric(4,2),挂衣 varchar(2),进仓时间 datetime) insert into #tb select 'a001',10,10,20,30,'y','2016-10-1' union all select 'a001',20,10,10,30,'y','2016-10-2' union all select 'a001',10,3,4,5,'y','2016-10-2' union all select 'b001',10,3,4,5,'y','2016-10-3' union all select 'b001',10,1,2,3,'y','2016-10-4' union all select 'c002',10,1,2,3,'y','2016-10-4' union all select 'd003',10,3,2,3,'y','2016-10-1' union all select 'g003',10,1,2,3,'y','2016-10-2' union all select 'b003',10,1,2,3,'y','2016-10-6' union all select 'f003',10,5,2,3,'y','2016-10-3' union all select 'a001',10,2,3,4,'n','2016-10-1' union all select 'a001',10,3,4,5,'n','2016-10-2' union all select 'b001',10,3,4,5,'n','2016-10-3' union all select 'b001',10,1,2,3,'n','2016-10-4' union all select 'c002',10,1,2,3,'n','2016-10-4' union all select 'd003',10,1,2,3,'n','2016-10-1' union all select 'g003',10,4,2,3,'n','2016-10-2' union all select 'b003',10,1,2,3,'n','2016-10-6' union all select 'f003',10,3,2,3,'n','2016-10-3' declare @dt datetime set @dt='2016-10-2' select t1.库名,t1.挂衣, case when t1.挂衣='n' then sum(t1.长*t1.宽*t1.高/1000.00*t1.件数) else 0 end as 总方, case when t1.挂衣='y' then sum (t1.件数) else 0 end as 总件 from (select (case when substring(库位,1,1) in('a','b','c') then '1库' else '2库' end)as 库名,件数,长,宽,高,挂衣,进仓时间 from #tb where 进仓时间 <=@dt )t1 group by t1.库名,t1.挂衣 |
我这样一张表 有字段 库位,件数,长,宽,高,挂衣，进仓时间（“挂衣”有两种状态 Y或N）
查询 如库位为“A”开头或“B"开头或"C"开头的为1库 "D"、“G”、“F”开头的为 2库
计算
当 1库“挂衣”=N 时在某段“进仓时间”内的立方总合（立方总合= sum（ （长*宽*高/1000）*件数）
当1库 挂衣”=Y 时在某段“进仓时间”内"件数"的总合
库2 计算同上
请问我要分别计算在一段时间内 库1、库2 的立方总合和件数总合sql语句怎么写