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#2
hu9jj2014-02-23 20:12
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程序代码：assume cs:code
a segment
db 1,2,3,4,5,6,7,8
a ends
b segment
db 1,2,3,4,5,6,7,8
b ends
c segment
db 0,0,0,0,0,0,0,0
c ends
code segment
mov bx,0
mov cx,8
mov ax,a
mov ds,ax
mov ax,0
s:add al,[bx]
add al,[bx+8]
mov [bx+16],al
inc bx
loop s
mov ax,4c00h
int 21h
code ends
end start
意思是 把a+b的值存到c中
add al,[bx+8]
mov [bx+16],al
这两行有什么问题没
a segment
db 1,2,3,4,5,6,7,8
a ends
b segment
db 1,2,3,4,5,6,7,8
b ends
c segment
db 0,0,0,0,0,0,0,0
c ends
code segment
mov bx,0
mov cx,8
mov ax,a
mov ds,ax
mov ax,0
s:add al,[bx]
add al,[bx+8]
mov [bx+16],al
inc bx
loop s
mov ax,4c00h
int 21h
code ends
end start
意思是 把a+b的值存到c中
add al,[bx+8]
mov [bx+16],al
这两行有什么问题没
[ 本帖最后由 e0a 于 2014-2-23 01:34 编辑 ]