用栈实现十进制向八进制（二进制）的转换

#include"stdio.h"
#include "stdlib.h"
#include"math.h"
#define ok 1
#define error 0
#define overflow -1

typedef int status;
typedef int selemtype;
#define stack_init_size 100
#define stackincrement 10

typedef struct sqstack
{
    selemtype * base;
    selemtype * top;
    int stacksize;
}sqstack;

status initstack(sqstack *s)
{
    (*s).base=(selemtype *)malloc(stack_init_size *sizeof(selemtype));
    if(!(*s).base) exit (overflow);
    (*s).top=(*s).base;
    (*s).stacksize=stack_init_size;
    return ok;
}

status stackempty(sqstack s)
{
    if(s.top==s.base)
        return ok;
    else
        return error;
}

status push(sqstack *s,selemtype e)
{
    if((*s).top-(*s).base>=(*s).stacksize)
    {
        (*s).base=(selemtype *)realloc((*s).base,((*s).stacksize+stackincrement)*sizeof(selemtype));
        if(!(*s).base) exit (overflow);
        (*s).top=(*s).base+(*s).stacksize;
        (*s).stacksize+=stackincrement;
    }
    *((*s).top)++=e;
    return ok;
}

status pop(sqstack *s,selemtype *e)
{
    if((*s).top==(*s).base)
        return error;
    *e=*--(*s).top;
    return ok;
}

main()
{
    sqstack s;
    selemtype e;
    int N;
    initstack(&s);
    scanf("%d",&N);
   
    while(N)
    {
                push(&s,N%2);     // 如果转换为八进制  将2改为8即可  下同
        N=N/2;            
    }
   
    while(!stackempty(s))
    {
        pop(&s,&e);
        printf("%d",e);
    }

}