求解密高手，大家都进来看看

fcl_admin`
--
CREATE TABLE IF NOT EXISTS `fcl_admin` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `adminName` varchar(50) DEFAULT NULL,
  `adminPass` varchar(50) DEFAULT NULL,
  `adminRank` int(11) DEFAULT NULL,
  `adminIp` varchar(50) DEFAULT NULL,
  `ipcheck` tinyint(4) DEFAULT NULL,
  `ip` varchar(255) DEFAULT NULL,
  `maccheck` tinyint(4) DEFAULT NULL,
  `mac` varchar(255) DEFAULT NULL,
  `hdecheck` tinyint(4) DEFAULT NULL,
  `hde` varchar(255) DEFAULT NULL,
  `cpucheck` tinyint(4) DEFAULT NULL,
  `cpu` varchar(255) DEFAULT NULL,
  `aid` int(11) DEFAULT '0',
  `mobilecheck` tinyint(4) DEFAULT NULL,
  `mobile` varchar(255) DEFAULT NULL,
  `mibaokacheck` tinyint(4) DEFAULT NULL,
  `mibaoka` varchar(255) DEFAULT NULL,
  `rights` text,
  PRIMARY KEY (`id`),
  KEY `id` (`id`)
) ENGINE=MyISAM  DEFAULT CHARSET=utf8 AUTO_INCREMENT=12 ;


INSERT INTO `fcl_admin` (`id`, `adminName`, `adminPass`, `adminRank`, `adminIp`, `ipcheck`, `ip`, `maccheck`, `mac`, `hdecheck`, `hde`, `cpucheck`, `cpu`, `aid`, `mobilecheck`, `mobile`, `mibaokacheck`, `mibaoka`, `rights`) VALUES
(11, 'admin', '21232f297a57a5a743894a0e4a801fc3', 1, NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL, NULL, 0, NULL, NULL, NULL, NULL, '1,1,1,1,1,1,1,1,1,1,1,1,1,0,0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0');


adminPass 的值：21232f297a57a5a743894a0e4a801fc3   是MD5 32位加密 已破解
求解密：rights 的值：1,1,1,1,1,1,1,1,1,1,1,1,1,0,0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0
 这是神马加密？
求原字符 和 这种类型加密方法