输入：
4
20070001 94 92 97 93 90
20070005 84 89 92 81 73
20070004 82 75 94 86 95
20070003 84 86 82 97 91
输出：
20070001 94 92 97 93 90 93.2
20070005 84 89 92 81 73 83.8
20070004 82 75 94 86 95 86.4
20070003 84 86 82 97 91 88.0
86.0 85.5 91.3 89.3 87.3
#include<iostream>
#include<string>
#include<iomanip>
using namespace std;
double bb=0,cc=0,dd=0,ee=0,ff=0;
int main()
{
for(int n;cin>>n;)
{
for(int i=1;i<=n;i++)
{
string a;
double b,c,d,e,f,ave;
cin>>a>>b>>c>>d>>e>>f;
ave=(b+c+d+e+f)/5;
cout<<a<<" "<<b<<" "<<c<<" "<<d<<" "<<e<<" "<<f<<" ";
cout<<fixed<<setprecision(1)<<ave<<endl;
bb+=b;cc+=c;dd+=d;ee+=e;ff+=f;
}
double q,w,e,r,t;
q=bb/n;
w=cc/n;
e=dd/n;
r=ee/n;
t=ff/n;
cout<<fixed<<setprecision(1)<<q<<" "<<fixed<<setprecision(1)<<w<<" "<<fixed<<setprecision(1)
<<e<<" "<<fixed<<setprecision(1)<<r<<" "<<fixed<<setprecision(1)<<t<<endl;
}
return 0;
} 我的输出，第二组开始都变成了一位小数，我只需要平均数为1位小数就行了啊。求解啊