#include<stdio.h>
#include<string.h>
#define N 5
struct add27xbb
{
    char name[10];
    char tel1[20];
    char tel2[20];
    char addr[15];
    char email[30];
};
     struct add27xbb people[N]={
     {"Jack","13800000000","13800000001","shanghai","Jack@},
     {"Mary","13900000000","13900000001","unknow","Mary@},
     {"John","15100000000","05168320000","beijing","John@},
     {"Smith","15200000000","unknow","unknow","    Rose#},
     {"Rose","15600000000","152000000002","xzit","unknow"}
                          };
main()
{
    char tel[20];
    char tel3[20];
    printf("输入你要查找的电话号码 :\n");
        gets(tel);
    printf("输入你要修改的电话号码：\n");
        gets(tel3);
    int flag=0;
    for(int i=0;i<N;i++)
    {
        if(strcmp(people[i].tel1,tel)==0)
        {
            printf("%s%15s%15s%15s%15s\n","姓名","电话1","电话2","住址","邮箱");
            printf("%s%15s%15s%15s%18s\n",people[i].name,people[i].tel1,people[i].tel2,people[i].addr,people[i].email);
            strcpy(people[i].tel1,tel3);
            puts("修改后的信息是：\n");
            printf("%s%15s%15s%15s%18s\n",people[i].name,people[i].tel1,people[i].tel2,people[i].addr,people[i].email);
            flag=1;
        }
        if(strcmp(people[i].tel2,tel)==0)
        {
            printf("%s%15s%15s%15s%15s\n","姓名","电话1","电话2","住址","邮箱");
            printf("%s%15s%15s%15s%18s\n",people[i].name,people[i].tel1,people[i].tel2,people[i].addr,people[i].email);
            strcpy(people[i].tel2,tel3);
            puts("修改后的信息是：\n");
            printf("%s%15s%15s%15s%18s\n",people[i].name,people[i].tel1,people[i].tel2,people[i].addr,people[i].email);
            flag=1;
        }               
    }
     if(flag==0)
     puts("查找的电话有错，请核对后输入。");
     
     
      
}
这是我对第三题的解法，但是我觉得有两个问题，一是其中一个电话号码是十二位，输入正确的电话号码也不能改对（因为是复制函数），二是有的电话都是unknow，这怎么改？还是我理解错了根本就不用管它们？

问题是修改号码用strcpy只能是都是11位的号码，但其中有个12位的错误号码啊，这该怎么办？

我记错了，谢谢了

好吧，应该是这样的，谢谢你。

好的，谢谢你。