static char s[3455641349];我的文件包含30亿个字符，系统显示数过大，超出内存，怎么定义啊？这是原代码，#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<math.h>

#define N 256

struct motif
{
  char name[20];
  float  number;
} lead[N];

void main()
{

/////计算TATA 保守性
   
    FILE *in,*out;
    in=fopen("sequence.txt","r");
    out=fopen("结果.txt","w");
    static char s[3455641349];
    char c[4]={'a','g','c','t'};
    int i=0,j=0,k=0,l=0,m=0,number=0;
    int person=0;
    float words=0;
    float expect=0;
   
    for(i=0;i<4;i++)
     for(j=0;j<4;j++)
      for(l=0;l<4;l++)
       for(m=0;m<4;m++)
           {
            lead[number].name[0]=c[i];
            lead[number].name[1]=c[j];
            lead[number].name[2]=c[l];
            lead[number].name[3]=c[m];
            number++;
           }

    while(!feof(in))
    {
      fgets(s,3455641349,in);
      if(s[0]=='@') break;
      for(i=0;i<3455641348;i++)
      {
       for(j=0;j<4;j++)
        for(k=0;k<4;k++)
         for(l=0;l<4;l++)
          for(m=0;m<4;m++)
              {
               if(s[i]==c[j]&&s[i+1]==c[k]&&s[i+2]==c[l]&&s[i+3]==c[m]&&s[i+4])
                  lead[person].number++;
               person++;
              }  
       person=0;
       words++;
      }
           
      for(i=0;i<3455641348;i++)
        s[i]=' ';
       }

    for(k=0;k<N;k++)        
        fprintf(out,"%s\t%f\t\n",lead[k].name,lead[k].number);
   
    fclose(out);
}



[ 本帖最后由 a13780393 于 2013-1-14 19:54 编辑 ]