private void button2_Click(object sender, EventArgs e)
{
SqlConnection conn = new SqlConnection("Data Source=PCName;Initial Catalog=DBName;Integrated Security=True");
//conn.Open();
if (conn.State == System.Data.ConnectionState.Open)
{
MessageBox.Show("测试连接成功！", "提示！");

}
else
{
MessageBox.Show("连接不成功！","提示！");
}

}

private void button3_Click(object sender, EventArgs e)
{
string PCName = this.texPCName.Text.Trim();
string DBName = this.texDBName.Text.Trim();
}
谁能教一下思路吗?

没人帮帮忙吗?

就是写代码连接数据库...但计算机名和数据库名都是前台手动输入的....然后在代码判断输入的计算名和数据库名是不否正确,是否连接成功......就是这样的.....

我等了好久好久啊...
string PCName = this.texPCName.Text.Trim();
string DBName = this.texDBName.Text.Trim();
string myconn ="Data Source=192.168.1.1;Initial Catalog=BlueHill;Integrated Security=True";
SqlConnection conn = new SqlConnection(myconn);
conn.Open();
if (conn.State == System.Data.ConnectionState.Open)
{
MessageBox.Show("测试连接成功！", "提示！");

}
else
{
MessageBox.Show("连接不成功！","提示！");
}

}
运行到conn.Open();的时候会出现异常现象这样的错误,要怎样处理?
还有我要读取PCName和DBName
Date Source=PCName;Initial Catalog=DBName;Integrated Security=True;这样写有错...那要怎样写..

请教高手啊

谢谢了..现在懂了