我的意思一个函数作为另一个函数的参数．下面怎么会出现：

26 D:\tcwork\人机对弈.c `ia' undeclared (first use in this function)

#include <stdio.h>
#include <conio.h>

int main(void)
{
int Funa(int ia);
int Funb(int ib, int Funa(int ia));

int ia = 5, ib = 10, ic;

ic = Funb(ib, Funa);

printf("ic = %d\n", ic);

getch();
return 0;
}

int Funa(int ia)
{
return ia + 10;
}

int Funb(int ib, int Funa(int ia))
{
return ( ib + Funa(ia) );
}

#include <stdio.h>
#include <conio.h>

int main(void)
{
int Funa(int ia);
int Funb(int ib, int (*Funa)(int ),int ia);

int ia = 5, ib = 10, ic;

ic = Funb(ib, Funa,ia);

printf("ic = %d\n", ic);

getch();
return 0;
}

int Funa(int ia)
{
return ia + 10;
}

int Funb(int ib, int (*Funa)(int ),int ia)
{

return ( ib + Funa(ia) );
}