读入一个自然数n，计算其各位数字之和，并用英文输出和的每一位数字。
要求：英文之间以空格隔开。
例如输入: 89563524，则有：8+9+5+6+3+5+2+4=42
 则屏幕上输出：four two
#include<stdio.h>
int main()
{
    int n,sum=0;
    printf("请输入一个整数");
    scanf("%d",&n);
    while (n)
    {
        sum=sum+n%10;
        n/=10;
    }
    printf("%d",sum);
}
int numadd(int x)   
{
    const char *str[]={"zero","one","two","three","four","five","six","seven","eight","nine"};
    while('\\n'!=(x=getchar()))
    {
        printf("%s ",str[x-'0']);
    }
    return 0;
}

我是新人刚开始写C语言

#include<stdio.h>
#include<string.h>
int main()
{
    int n,sum=0;
    int numadd(int x);
    char sn[10];
    printf("请输入一个整数");
    scanf("%d",&n);
             
    while (n)
    {
        sum=sum+n%10;
        n/=10;
    }
    printf("%d\n",sum);
    
    sprintf(sn,"%d",sum);
    for(int i=0;i<strlen(sn);i++)
    {
        numadd(sn[i]);
    }
    
}
int numadd(int x)    
{
    const char *str[]={"zero","one","two","three","four","five","six","seven","eight","nine"};
        printf("%s ",str[x-'0']);
    return 0;
}