package mistake;
import java.util.BitSet;
public class BitSetDemo {

    /**
     * @param args
     */
    public static void main(String[] args) {
        // TODO Auto-generated method stub
        BitSet bits1 = new BitSet(16);
         BitSet bits2 = new BitSet(16);
         
         // set some bits
         for(int i=0; i<16; i++) {
            if((i%2) == 0) bits1.set(i);
            if((i%5) != 0) bits2.set(i);
         }
         System.out.println("Initial pattern in bits1: ");
         System.out.println(bits1);
         System.out.println("\nInitial pattern in bits2: ");
         System.out.println(bits2);

         // AND bits
         bits2.and(bits1);
         System.out.println("\nbits2 AND bits1: ");
         System.out.println(bits2);

         // OR bits
         bits2.or(bits1);
         System.out.println("\nbits2 OR bits1: ");
         System.out.println(bits2);

         // XOR bits
         bits2.xor(bits1);
         System.out.println("\nbits2 XOR bits1: ");
         System.out.println(bits2);

    }

}


这是在网上看到的  为什么逻辑或的输出是：
bits2 OR bits1:
{0, 2, 4, 6, 8, 10, 12, 14}


还有这个Bitset是怎么理解的.

请大神指教下

Bitset是通过long[]实现的，存储的是0/1

首先
Bitset中运算方法and/or/xor/andNot都是void类型的，计算结果存储在调用方法的对象上
在执行完bits2.and(bits1); bits2本身的值已经变了
其次
System.out.println(bits2); 打印出来的是bits2中非0值的下标，并不是真实值