#include <stdio.h>
#include <malloc.h>
typedef int ElemType;
typedef struct Node
{
    ElemType data;
    struct Node *next;
} Node;
typedef struct Node *Linklist;
Linklist Create(Linklist head);

int main(void)
{
    Linklist head;
    Create(head);
    printf("--------------");
    while (head->next != NULL)
        printf("%d.\n", head->data);
    return 0;
}

Linklist Create(Linklist head)
{
    int x, i = 1;
    Linklist p, q;
    q = head;
    printf("Your %d input:(0 to quit)\n", i);
    scanf("%d", &x);
    while (x != 0)
    {
        p = (Node *)malloc(sizeof(Node));
        p->data = x;
        p->next = NULL;
        q->next = p;
        q = p;
        scanf("%d", &x);
    }
    return head;
}

以上是我的代码，每当我输入数据的时候，程序就自动停止了。我到底是什么地方出错了？
还有 typedef struct Node * Linklist
Linklist p 声明的是一个指向Node的指针吗
那Linklist *p 又是什么意思呢？指向指针的指针？

按照楼主的意图实现的代码
不知道可用不？

#include <stdio.h>
#include <stdlib.h>

typedef struct node {
    int data;
    struct node *next;
} ND, *PN;

void create_list(PN head);
void free_list(PN head);

int main(void) {
    ND HEAD;
    PN head = &HEAD, cur = NULL;
    create_list(head);
    puts("--------------");

    for(cur = head; cur; cur = cur->next)
        printf("%d\n", cur->data);

    free_list(head->next);

    return 0;
}

void create_list(PN head) {
    int x, i = 1;
    PN new, cur = head;
    printf("Your %d input:(0 to quit)\n", i);
    scanf("%d", &x);

    while(x != 0) {
        new = malloc(sizeof(ND));
        new->data = x;
        cur->next = new;
        cur = new;
        scanf("%d", &x);
    }
    cur->next = NULL;
}

void free_list(PN head) {
    PN p;

    while(head != NULL) {
        p = head->next;
        free(head);
        head = p;
    }
}