struct date
{
    int year;
    int month;
    int day;
};
void main()
{
    void cf(struct date *p);
    struct date s1,*p;
    printf("请输入今天的日期:  ");
    scanf("%d %d %d",&s1.year,&s1.month,&s1.day);
    p=&s1;
    cf(p);
}
void  cf(struct date *p)
{   
    struct date s2;
    if(p->day<28)
        s2.year=p->year;
        s2.month=p->month;
        s2.day=p->day+1;
    else if(p->day==28)
         if(p->year%4==0&&p->year%100!=0||p->year%400==0)
           s2.year=p->year;
           s2.month=p->month;
           s2.day=p->day+1;
         else
             s2.year=p->year;
             if(p->month==2)
               s2.month=3;
               s2.day=1;
             else
               s2.month=p->month;
               s2.day=p->day+1;
     else if(p->day==29)
         if(p->year%4==0&&p->year%100!=0||p->year%400==0)
             if(p->month==2)
               s2.month=3;
               s2.day=1;
             else
               s2.year=p->year;
               s2.month=p->month;
               s2.day=p->day+1;
    else if(p->day==30)
        if(p->month==1||3||5||7||8||10||12)
           s2.year=p->year;
           s2.month=p->month;
           s2.day=p->day+1;
        else
           s2.year=p->year;
           s2.month=p->month+1;
           s2.day=1;
    else
        if(p->month==12)
            s2.year=p->year+1;
        else
           s2.year=p->year;
           s2.month=p->month+1;
           s2.day=1;
    printf("输出新的日期:%d %d %d\n",s2.year,s2.month,s2.day);
}







            


 

寫得太亂了。。

是啊，不知怎么简化

应该先判断月份会简单一些，除了2月，其他月份是跟闰年无关的

是2月，再判断是不是闰年

#include<stdio.h>
//#include<stdlib.h>
struct date
{
    int year;
    int month;
    int day;
};
void main()
{
    void cf(struct date *p);
    struct date s1,*p;
    printf("请输入今天的日期:  ");
    while(scanf("%d %d %d",&s1.year,&s1.month,&s1.day))
        {p=&s1;
        cf(p);
        }
    //system("pause");
}
void  cf(struct date *p)
{   
    struct date s2;
    s2.day=p->day;
    s2.month=p->month;
    s2.year=p->year;
    switch(s2.month)
    {
        case 1:
        case 3:
        case 5:
        case 7:
        case 8:
        case 10:
                if(s2.day==31)
                    {
                        ++s2.month;
                        s2.day=1;
                    }
                    else
                    {++s2.day;}
                break;
        case 12:
            if(s2.day=31)
                    {
                        ++s2.year;
                        s2.day=1;
                        s2.month=1;
                    }
                    else
                    {++s2.day;}
                break;
        case 4:
        case 6:
        case 9:
        case 11:
            if(s2.day==30)
                    {
                        ++s2.month;
                        s2.day=1;
                    }
                    else
                    {++s2.day;}
                break;
        case 2:
            if(((s2.year)%4==0)&&((s2.year)%100!=0)||((s2.year)%400==0))
                {
                    if(s2.day==29)
                        {
                            ++s2.month;
                            s2.day=1;
                        }
                        else
                        {++s2.day;}
                }
            else
                {
                    if(s2.day==28)
                        {
                            ++s2.month;
                            s2.day=1;
                        }
                        else
                        {++s2.day;}   
                }
                break;
    }
    printf("输出新的日期:%d %d %d\n",s2.year,s2.month,s2.day);

}

//我测试了几个数据，应该没错
//没有添加输入数据是否合理的判断程序 例如2014 4 56，2014 2 29
//判断情况复杂，用switch

bool 当前年是闰年吗( 年 )
{
    return 年%400==0 || (年%4==0 && 年%100!=0);
}

int 获得当前月之天数( 年，月 )
{
    static int ms[] = { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
    return ms[月-1] + (月==2 && 当前年是闰年吗(年));
}

auto 明天的日期( 年，月，日 )
{
    if( 日 < 获得当前月之天数(年，月) )
    {
        日 = 日+1;
        return;
    }

    年 = 年 + (月==12);
    月 = 月%12 + 1;
    日 = 1;
}

[ 本帖最后由 rjsp 于 2014-7-25 10:42 编辑 ]

中英文混搭的style的确与众不同，呵呵

printf scanf运行为undeclared identifier，标准库函数，怎么会成为未定义标识符

无代码无真相

struct date
{
    int year;
    int month;
    int day;
};
void main()
{
    void cf(struct date *p);
    struct date s1,*p;
    printf("请输入今天的日期:  ");
    scanf("%d %d %d",&s1.year,&s1.month,&s1.day);
    p=&s1;
    cf(p);
}
void  cf(struct date *p)
{   
    struct date s2;
    if(p->day<28)
    {
        s2.year=p->year;
        s2.month=p->month;
        s2.day=p->day+1;
    }
    else if(p->day==28)
    {
         if(p->year%4==0&&p->year%100!=0||p->year%400==0)
         {
           s2.year=p->year;
           s2.month=p->month;
           s2.day=p->day+1;
         }
         else
             s2.year=p->year;
             if(p->month==2)
             {
               s2.month=3;
               s2.day=1;
             }
             else
             {
               s2.month=p->month;
               s2.day=p->day+1;
             }
    }
    else if(p->day==29)
         if(p->year%4==0&&p->year%100!=0||p->year%400==0)
             if(p->month==2)
             {
               s2.year=p->year;
               s2.month=3;
               s2.day=1;
             }
             else
             {
               s2.year=p->year;
               s2.month=p->month;
               s2.day=p->day+1;
             }
         else
         {
            s2.year=p->year;
            s2.month=p->month;
            s2.day=p->day+1;
         }
    else if(p->day==30)
        if(p->month==1||3||5||7||8||10||12)
        {
           s2.year=p->year;
           s2.month=p->month;
           s2.day=p->day+1;
        }
        else
        {
           s2.year=p->year;
           s2.month=p->month+1;
           s2.day=1;
        }
    else
        if(p->month==12)
        {
            s2.year=p->year+1;
            s2.month=1;
            s2.day=1;
        }
        else
        {
           s2.year=p->year;
           s2.month=p->month+1;
           s2.day=1;
        }
    printf("输出新的日期:%d年%d月%d日\n",s2.year,s2.month,s2.day);
}