执行时候说文件结尾有问题？？由于换了系统是乱码。所以下面的****都代表
中文字符。可能有些符号是中文全角符号，也请多多包含~~~
下面是我的代码:
(1)shell部分：
#!/bin/bash
#c成绩存取系统(001.sh)
echo '********'
echo -e '\t\t**********\n'
echo -e '\t\t***********\n'
read A
 
./03.out
echo -e '\t\t\t1.*******\n'
echo -e '\t\t\t2.********\n'
echo -e '\t\t\t3.**********\n'
echo -e '\n\n*************:'
 
read B
if ($B=1)
 then (echo '******************\n'
       read C
       ./2.out > $C)   
else
 if ($B=2)
  then (echo '****************\n'
        read D
        ./1.out < $D)
 else echo '*********'
 
fi
(2)01.c部分：
#include <stdio.h>
#define MAX 10
int main (void)
{
 system ("cls");
 int number;
 char sex;
 char name[MAX];
 float Chinese, Maths, English;
  
 scanf ("%d", &number);
 while (number >= 0)
 {
  printf ("%6d", number);
  getchar ();
  scanf ("%c", &sex);
  printf ("%6c", sex);
  scanf ("%s", name);
  printf ("%15s", name);
  scanf ("%f", &Chinese);
  printf ("%6.1f", Chinese);
  scanf ("%f", &Maths);
  printf ("%6.1f", Maths);
  scanf ("%f", &English);
  printf ("%6.1f", English);
  printf ("\n");
  scanf ("%d", &number);
 }
  
 printf ("*************\n");
 return 0;
}
 
(3)02.c部分
#include <stdio.h>
#define MAX 10
int main (void)
{
 system ("cls");
 int number;
 char sex;
 char name[MAX];
 float Chinese, Maths, English;
  
 printf ("**********\n");
 scanf ("%d", &number);
 while (number >= 0)
 {
  printf ("%6d", number);
  getchar ();
  printf ("*********\n");
  scanf ("%c", &sex);
  printf ("%6c", sex);
  printf ("****************\n");
  scanf ("%s", name);
  printf ("%15s", name);
  printf ("**************\n");
  scanf ("%f", &Chinese);
  printf ("%6.1f", Chinese);
  printf ("***************\n");
  scanf ("%f", &Maths);
  printf ("%6.1f", Maths);
  printf ("***************\n");
  scanf ("%f", &English);
  printf ("%6.1f", English);
  printf ("\n");
  printf ("*******\n");
  scanf ("%d", &number);
 }
  
 printf ("************\n");
 return 0;
}