分析程序得结果：
1.#include<iostream.h>
class sample
{
int x;
public:
viod setx(int i){x=i;}
int putx(){return x;}
};
void mani()
{ sample*p; sample A[3]; A[0].setx(5); A[1].setx(6); A[2].setx(7); p=&A[0];
for(int j=0;j<3;j++)
cout<<p++ → putx()<<" ";
cout<<end1;
}

2.#include<iostream.h>
class Location
{
public:
Location (int xx=0, int yy=0){X=xx; Y=yy;}
Location (Location & p);
～Location(){cout<<X<<","<<Y<<"Object destroyed".<<end1;}
int GetX(){return X;}
int GetY(){return Y;}
private: int X,Y;
};
location::location(location&p)
{X=p.x;Y=p.y;cout<<"copy_constructor called."<<endl;}
void f(location p){cout<<"Function:"<<p.GetX()<<","<<p.GetY()<<endl;}
void main()
{LOcation A(1,2);f(A);}
以上程序的执行结果是————。
编程题
1。定义一个SHAPE抽象类,在此基础上派生出Circle(圆形)和Square(矩形)类，二者都有GetArea()函数计算对象的面积，GetPerim()函数计算对象的 周长。
2。使用重载函数编程序分别把俩个数.三个数和四个数从大到小排列。
初学者啦，望各位写结果的时候，帮我分析一下程序，

明确告诉你  上面的程序没有办运行~~                                                                                

#include<iostream.h>
class sample
{
int x;
public:
void setx(int i)
{
x=i;
}
int putx()
{
return x;
}
};
void main()
{
sample*p;
sample A[4];
A[0].setx(5);
A[1].setx(6);
A[2].setx(7);
A[3].setx(8);
p=&A[0];
for(int j=0;j<4;j++,p++)
cout<<p->putx()<<" ";
cout<<endl;
}
============================================================================================================
#include<iostream.h>
class Location
{
public:
Location(int xx=0,int yy=0)
{
X=xx;
Y=yy;
}
Location(Location & p);
~Location()
{
cout<<X<<","<<Y<<"Object destroyed"<<endl;
}
int GetX()
{
return X;
}
int GetY()
{
return Y;
}
private:
int X,Y;
};
Location::Location(Location &p)
{
X=p.X;
Y=p.Y;
cout<<"copy_constructor called."<<endl;
}
void f(Location p)
{
cout<<"Function:"<<p.GetX()<<","<<p.GetY()<<endl;
}
void main()
{
Location A(1,2);
f(A);
}