http://acm.tju.edu.cn/toj/showp1031.html
比代码短，我的代码是1.0K，自认为非常精短
--------------------------------------------------------------------------------
Judge Status Prob. Lang. Code Time Memory User
Accepted 1031 C++ 1.0K 0:00.00 672K lecoo

用了672K的内存.....

鄙人用两种方法做了..一种用了16K内存,一种用了144K内存 也都是0MS

非常有兴趣拜读楼主大人的1K代码..请楼主发给我观摩一下.

感激不尽...

你用了16K内存？不敢相信啊，贴上来看看
[UserName=stupid_boy]

#include <stdio.h>

#define PC(x) putchar(x)
#define PCD(x,y) putchar(digits[ch-'0'][x]?y:' ')
int digits[10][7]={1,0,1,1,1,1,1,0,0,0,0,1,0,1,1,1,1,0,1,1,0,1,1,1,0,1,0,1,0,1,0,1,
    1,0,1,1,1,1,1,0,0,1,1,1,1,1,0,1,1,1,0,0,0,1,0,1,1,1,1,1,1,1,1,1,1,1,1,1,0,1,};
void out(int s,char ch,int k)
{
    switch(k){
    case 0:
    case 2:
    case 4:
        PC(' ');
        for(int i=0;i<s;i++){
            PCD(k/2,'-');
        }
        PC(' ');
        break;
    case 1:
    case 3:
        PCD(k+2,'|');
        for(int i=0;i<s;i++){
            PC(' ');
        }
        PCD(k+3,'|');
        break;
    }
}
void out(int s,char* str,int suit)
{
    out(s,*str,suit);
    for(char *p=str+1;*p;p++){
        PC(' ');
        out(s,*p,suit);
    }
}
int main()
{
    char buf[100];
    int s;
    while(scanf(\"%d %s\",&s,buf)!=EOF && s){
        out(s,buf,0);
        PC('\n');
        for(int i=0;i<s;i++){
            out(s,buf,1);
            PC('\n');
        }
        out(s,buf,2);
        PC('\n');
        for(int i=0;i<s;i++){
            out(s,buf,3);
            PC('\n');
        }
        out(s,buf,4);
        PC('\n');
        PC('\n');
    }
}

[/UserName]

PKU上面memory是16k,这个是比较好的方法

[UserName=leeco]

#include <stdio.h>
#include <string.h>

int code[5][30]=
{
{0,1,0,0,0,0,0,1,0,0,1,0,0,0,0,0,1,0,0,1,0,0,1,0,0,1,0,0,1,0},
{1,0,1,0,0,1,0,0,1,0,0,1,1,0,1,1,0,0,1,0,0,0,0,1,1,0,1,1,0,1},
{0,0,0,0,0,0,0,1,0,0,1,0,0,1,0,0,1,0,0,1,0,0,0,0,0,1,0,0,1,0},
{1,0,1,0,0,1,1,0,0,0,0,1,0,0,1,0,0,1,1,0,1,0,0,1,1,0,1,0,0,1},
{0,1,0,0,0,0,0,1,0,0,1,0,0,0,0,0,1,0,0,1,0,0,0,0,0,1,0,0,1,0}
};

int main()
{
int i,j,m,n,k,k1,posS;
char s[9];
while(1){
scanf("%d",&n);
scanf("%s",&s);
if(n==0&&strcmp(s,"0")==0)break;

for(i=0; i<5; i++)
{
if(!(i%2))
{
for(posS=0; s[posS]!='\0'; posS++)
{
for(m=0,j=(int)(s[posS]-'0')*3; m<3; m++,j++)
{
if((j%3==0||(j+1)%3==0)&&(i%2==0))
printf(" ");
else
{
for(k=0; k<n; k++)
{
if(code[i][j]) printf("-");
else printf(" ");
}
}
}
printf(" ");
}
printf("\n");
}
else
{
for(k=0; k<n; k++)
{
for(posS=0; s[posS]!='\0'; posS++)
{
for(m=0,j=(int)(s[posS]-'0')*3; m<3; m++,j++)
{
if(j%3==0||(j+1)%3==0)
{
if(code[i][j]) printf("|");
else printf(" ");
}
else
for(k1=0; k1<n; k1++)
printf(" ");
}
printf(" ");
}
printf("\n");
}
}
}
printf("\n");
}

return 0;
}

[/UserName]

[UserName=leeco]144k那个是最笨的方法， 用数组做的..一点技术都没有,纯粹的体力劳动

我就不发那个了.

随便问一下.你是哪个大学的?大几了?

我写的代码很长.今天看了你的代码,有收获!![/UserName]

leeco你的代码我复制到VC里面运行不了.....

你是在存的时候就分成了"顶行","上段","中行","下段","底行"这五个部分？

你在C++的编译器上编译吧，可能是我for(int...)这样的语法写习惯了，我一直是用C++的
哦对还重载了一个out函数

[此贴子已经被作者于2007-7-11 16:05:58编辑过]

饿.
code数组里面就是这样了
饿.

上海师范大学，将要大三了