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标题:小白求教 这个代码没有看懂,求解
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siriussonny
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小白求教 这个代码没有看懂,求解
#include <iostream>
#include <iomanip>
#include <cstdlib>
#include <cstring>
#include <cctype>
#include <cmath>
#include <stdio.h>
#include <string.h>
#include <windows.h>
using namespace std;
const char Tab=0x9;
const int  DIGIT=1;
const int MAXSIZE=16384;
char s[MAXSIZE],*endss;
int pcs=15;
double fun(double x,char op[],int *iop) {

        switch (op[*iop-1]) {
        case  7: x=sin(x);  (*iop)--;break;
        case  8: x=cos(x);  (*iop)--;break;
        case  9: x=tan(x);  (*iop)--;break;
        case 10: x=sqrt(x); (*iop)--;break;
        case 11: x=asin(x); (*iop)--;break;
        case 12: x=acos(x); (*iop)--;break;
        case 13: x=atan(x); (*iop)--;break;
        case 14: x=log10(x);(*iop)--;break;
        case 15: x=log(x);  (*iop)--;break;
        case 16: x=exp(x);  (*iop)--;break;
        }
    return x;
}
double calc(char *expr,char **addr) {
    static int deep; //递归深度
    static char *fname[]={ "sin","cos","tan","sqrt","arcsin","arccos","arctan","lg","ln","exp",NULL};
    double ST[10]={0.0}; //数字栈
    char op[10]={'+'}; //运算符栈
    char c,*rexp,*pp,*pf;
    int ist=1,iop=1,last,i;
    if (!deep) {
        pp=pf=expr;
        do {
            c = *pp++;
            if (c!=' '&& c!=Tab)
                *pf++ = c;
        } while (c!='\0');
    }
    pp=expr;
    if ((c=*pp)=='-'||c=='+') {
        op[0] = c;
        pp++;
    }
    last = !DIGIT;
    while ((c=*pp)!='\0') {
        if (c=='(') {//左圆括弧
            deep++;
            ST[ist++]=calc(++pp,addr);
            deep--;
            ST[ist-1]=fun(ST[ist-1],op,&iop);
            pp = *addr;
            last = DIGIT;
            if (*pp == '('||isalpha(*pp) && strnicmp(pp,"Pi",2)) {//目的是:当右圆括弧的右恻为左圆括弧或函数名字时,默认其为乘法
                op[iop++]='*';
                last = !DIGIT;
                c = op[--iop];
                goto operate ;
            }
        }
        else if (c==')') {//右圆括弧
            pp++;
            break;
        } else if (isalpha(c)) {
            if (!strnicmp(pp,"Pi",2)) {
                if (last==DIGIT) {
                    cout<< "π左侧遇)" <<endl;exit(1);
                }
                ST[ist++]=3.14159265358979323846264338328;
                ST[ist-1]=fun(ST[ist-1],op,&iop);
                pp += 2;
                last = DIGIT;
                if (!strnicmp(pp,"Pi",2)) {
                    cout<< "两个π相连" <<endl;exit(2);
                }
                if (*pp=='(') {
                    cout<< "π右侧遇(" <<endl;exit(3);
                }
            } else {
                for (i=0; (pf=fname[i])!=NULL; i++)
                    if (!strnicmp(pp,pf,strlen(pf))) break;
                if (pf!=NULL) {
                    op[iop++] = 07+i;
                    pp += strlen(pf);
                } else {
                    cout<< "陌生函数名" <<endl;exit(4);
                }
            }
        } else if (c=='+'||c=='-'||c=='*'||c=='/'||c=='^') {
            char cc;
            if (last != DIGIT) {
                cout<< "运算符粘连" <<endl;exit(5);
            }
            pp++;
            if (c=='+'||c=='-') {
                do {
                    cc = op[--iop];
                    --ist;
                    switch (cc) {
                    case '+':  ST[ist-1] += ST[ist];break;
                    case '-':  ST[ist-1] -= ST[ist];break;
                    case '*':  ST[ist-1] *= ST[ist];break;
                    case '/':  ST[ist-1] /= ST[ist];break;
                    case '^':  ST[ist-1] = pow(ST[ist-1],ST[ist]);break;
                    }
                } while (iop);
                op[iop++] = c;
            } else if (c=='*'||c=='/') {
operate:        cc = op[iop-1];
                if (cc=='+'||cc=='-') {
                    op[iop++] = c;
                } else {
                    --ist;
                    op[iop-1] = c;
                    switch (cc) {
                    case '*':  ST[ist-1] *= ST[ist];break;
                    case '/':  ST[ist-1] /= ST[ist];break;
                    case '^':  ST[ist-1] = pow(ST[ist-1],ST[ist]);break;
                    }
                }
            } else {
                cc = op[iop-1];
                if (cc=='^') {
                    cout<< "乘幂符连用" <<endl;exit(6);
                }
                op[iop++] = c;
            }
            last = !DIGIT;
        } else {
            if (last == DIGIT) {
                cout<< "两数字粘连" <<endl;exit(7);
            }
            ST[ist++]=strtod(pp,&rexp);
            ST[ist-1]=fun(ST[ist-1],op,&iop);
            if (pp == rexp) {
                cout<< "非法字符" <<endl;exit(8);
            }
            pp = rexp;
            last = DIGIT;
            if (*pp == '('||isalpha(*pp)) {
                op[iop++]='*';
                last = !DIGIT;
                c = op[--iop];
                goto operate ;
            }
        }
    }
    *addr=pp;
    if (iop>=ist) {
        cout<< "表达式有误" <<endl;exit(9);
    }
    while (iop) {
        --ist;
        switch (op[--iop]) {
        case '+':  ST[ist-1] += ST[ist];break;
        case '-':  ST[ist-1] -= ST[ist];break;
        case '*':  ST[ist-1] *= ST[ist];break;
        case '/':  ST[ist-1] /= ST[ist];break;
        case '^':  ST[ist-1] = pow(ST[ist-1],ST[ist]);break;
        }
    }
    return ST[0];
}
int main(int argc,char **argv) {
    if (argc<=1) {
        if (GetConsoleOutputCP()!=936) system("chcp 936>NUL");//中文代码页
        cout << "计算函数表达式的值。"<<endl;
        cout<<"(),+,-,*,/,^,Pi,sin,cos,tan,sqrt,arcsin,arccos,arctan,lg,ln,exp"<<endl;
        cout<<"按回车获得答案无需输入等号"<<endl;
        cout<<"三角函数仅支持弧度制"<<endl;
        while (1) {
            cout << "请输入表达式:";
            gets(s);
            if (s[0]==0) break;//
            cout << s <<"=";
            cout << setprecision(15) << calc(s,&endss) << endl;
        }
    } else {
        strncpy(s,argv[1],MAXSIZE-1);s[MAXSIZE-1]=0;
        if (argc>=3) {
            pcs=atoi(argv[2]);
            if (pcs<0||15<pcs) pcs=15;
            printf("%.*lf\n",pcs,calc(s,&endss));
        } else {
            printf("%.15lg\n",calc(s,&endss));
        }
    }

能不能大概给我讲一下 每个部分的作用?
比如operate部分 double calc部分?
感激不尽
2017-12-28 22:17
stop1204
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看着就象是计算器

hl928452957@gmail点com

2017-12-29 09:27
liaohs
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这个程序是一个表达式求值程序,可以计算包含四则运算和三角函数的表达式。

程序设计比较混乱,结构不合理。

正确的方法应该使用编译原理和算符优先分析方法,写出的程序应该简练得多。

建议不要读这个程序,去学编译吧。
2017-12-30 21:06







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