题目的要求是:用户输入一个运算式后回车,出现结果.例如,输入"1+2",回车,输出3;输入"140/2",回车,输出70.以下是我的未完成的程序:

import java.io.*;

public class Calculation {
public static void main(String args[]) throws IOException{
BufferedReader br= new BufferedReader(new InputStreamReader(System.in));
String str=br.readLine();
int length=str.length();
int operand1,operand2,result=0;
String oper1="",oper2="";
boolean afterOper1=false;
char c,flag='0';
for(int i=0;i<length;i++){
c=str.charAt(i);
if(c!='+' && c!='-' && c!='*' && c!='/'){
if(!afterOper1){
oper1+=c;
}else{
oper2+=c;
}
}else{
afterOper1=true;
flag=c;
}
}
operand1=Integer.parseInt(oper1);
operand2=Integer.parseInt(oper2);
switch(flag){
case'+':result=operand1+operand2;break;
case'-':result=operand1-operand2;break;
case'*':result=operand1*operand2;break;
case'/':result=operand1/operand2;break;
}
System.out.println(result);
}
}
在这段代码里面,我只完成了两个操作数都是正数的情况.但是当操作数为负数时,我想加入符号位来判断.下面的代码是我修改后的代码:

import java.io.*;

public class Calculation {
public static void main(String args[]) throws IOException{
BufferedReader br= new BufferedReader(new InputStreamReader(System.in));
String str=br.readLine();
int length=str.length();
int operand1,operand2,result=0;
String oper1="",oper2="";
boolean afterOper1=false;
char c,flag='0';
for(int i=0;i<length;i++){
c=str.charAt(i);
if(c!='+' && c!='-' && c!='*' && c!='/'){
if(!afterOper1){
oper1+=c;
}else{
oper2+=c;
}
}else{
afterOper1=true;
flag=c;
}
}

c=oper1.charAt(0);//取出第一个操作数的首位来判断是数字还是负号
System.out.println(c);//当输入的第一个操作数有负号时,报错

operand1=Integer.parseInt(oper1);
operand2=Integer.parseInt(oper2);
switch(flag){
case'+':result=operand1+operand2;break;
case'-':result=operand1-operand2;break;
case'*':result=operand1*operand2;break;
case'/':result=operand1/operand2;break;
}
System.out.println(result);
}
}
上面的代码也是未完成,因为我想判断第一个操作数的符号时出现了错误.例如,当输入"-3+2"时,报错:
Exception in thread "main" java.lang.StringIndexOutOfBoundsException: String index out of range: 0
at java.lang.String.charAt(Unknown Source)
at src.Calculation.main(Calculation.java:28)
百思不得其解,请教高手为什么会这样?

你的if,else语句有问题。当第一个数是负数时，if语句不会执行的
oper1里什么都没有.

完整程序已经做出来了:
import java.io.*;

public class Calculation {
public static void main(String args[]) throws IOException{
BufferedReader br= new BufferedReader(new InputStreamReader(System.in));
String str=br.readLine();
int length=str.length();
//operand1 is the 1st operand,operand2 is the 2nd
int operand1,operand2,result=0;
//oper1 is the 1st string of 1st operand,oper2 is the 2nd string of 2nd operand
String oper1="",oper2="";
//if afterOper1=true,operand2 will be counted,or operand1 will be counted
boolean afterOper1=false;
//flag is the operation
char c,flag='0';
//these two booleans are used to see whether the operands are minus
boolean firstMinus=false,secondMinus=false;
//to see whether the 1st operand is minus or not
c=str.charAt(0);
if(c=='-'){
firstMinus=true;
str=str.substring(1,length);
length--;
}
for(int i=0;i<length;i++){
c=str.charAt(i);
if(c!='+' && c!='-' && c!='*' && c!='/'){
if(!afterOper1){
oper1+=c;
}else{
oper2+=c;
}
}else{
afterOper1=true;
}
}
//get the operation
flag=str.charAt(oper1.length());
//to see whether the 2nd operand is minus or not
c=str.charAt(oper1.length()+1);
if(c=='-'){
secondMinus=true;
}
operand1=Integer.parseInt(oper1);
if(firstMinus) operand1=-operand1;
operand2=Integer.parseInt(oper2);
if(secondMinus) operand2=-operand2;
switch(flag){
case'+':result=operand1+operand2;break;
case'-':result=operand1-operand2;break;
case'*':result=operand1*operand2;break;
case'/':result=operand1/operand2;break;
}
System.out.println(result);
}
}
大家还有什么更好的方法吗?请教一下