用700元购入物品的程序，执行后得到


Line up;
1:notebook \150
2:mechanical pencil \180
3:highlight marker set \210
4:eraser \110
Now You have \700 now. What do you want?
Input number of items:1
You've got a notebook.
Now You have \550 now. What do you want?
Input number of items:2
You've got a mechanical pencil.
Now You have \370 now. What do you want?
Input number of items:3
You've got highlight marker set.
Now You have \160 now. What do you want?
Input number of items:4
You've got a eraser.

Total items : 4
Remaining money : 50



或

Line up;
1:notebook \150
2:mechanical pencil \180
3:highlight marker set \210
4:eraser \110
Now You have \700 now. What do you want?
Input number of items:0
Error! Choose number 1-4 .
Now You have \700 now. What do you want?
Input number of items:1
You've got a notebook.
Now You have \550 now. What do you want?
Input number of items:1
You've got a notebook.
Now You have \400 now. What do you want?
Input number of items:1
You've got a notebook.
Now You have \250 now. What do you want?
Input number of items:1
You've got a notebook.

Total items : 4
Remaining money : 100.

[ 本帖最后由 我是含羞草 于 2015-5-21 16:27 编辑 ]

#include<stdio.h>
int min(int a,int b,int c,int d){
    return a>b?b:a>c>d?d:c?c>d?d:c:a>b?b:a;
}
main(){
    printf("Line up;\n");
    printf("1:notebook \\150\n");
    printf("2:mechanical pencil \\180\n");
    printf("3:highlight marker set \\210\n");
    printf("4:eraser \\110\n");
    int ch,sum=700,count=0;  
    while(sum>min(110,210,280,150)){
        printf("Now You have \\%d now. What do you want?\n\nInput number of items:",sum);
        scanf("%d",&ch);
        switch(ch){
            case 1:sum-=150;printf("You've got a notebook.\n");break;
            case 2:sum-=180;printf("You've got a mechanical pencil.\n");break;
            case 3:sum-=210;printf("You've got highlight marker set.\n");break;
            case 4:sum-=110;printf("You've got a eraser.\n");
        }
        count++;
    }
    printf("\n\nTotal items : %d\n",count);
    printf("Remaining money : %d",sum);
}