//author: Yuchao liao
//2014/3/11
//a complex number calculator
//The program should ask the user which of the five operations he wants to perform. It then asks the user to
//enter the appropriate values for the complex numbers and performs the necessary computation.

#include<stdio.h>
#include<math.h>
#define PI 3.1415926

void read_complex(float *z_r, float *z_i) // reads a complex number from the keyboard
{
    float a,b;
    printf("Enter a complex number:");
    scanf_s("%f %f",&a,&b);
    *z_r=a;
    *z_i=b;
}

void print_complex(float z_r, float z_i)
{
    printf("result:%.1f+(%.1fi)",z_r,z_i);
}

void add_complex(float z1_r, float z1_i, float z2_r, float z2_i, float *z3_r, float *z3_i) // z3=z1+z2
{
    *z3_r=z1_r+z2_r;
    *z3_i=z1_i+z2_i;
}

void sub_complex(float z1_r, float z1_i, float z2_r, float z2_i, float *z3_r, float *z3_i) // z3=z2-z1
{
    *z3_r=z1_r-z2_r;
    *z3_i=z1_i-z2_i;
}

void mul_complex(float z1_r, float z1_i, float z2_r, float z2_i, float *z3_r, float *z3_i) //z3=z1*z2
{
    *z3_r=z1_r*z2_r-z1_i*z2_i;
    *z3_i=z1_i*z2_r+z2_i*z1_r;
}

void div_complex(float z1_r, float z1_i, float z2_r, float z2_i, float *z3_r, float *z3_i) // z3=z1/z2
{
    *z3_r=(z1_r*z2_r+z1_i*z2_i)/(z2_r*z2_r+z2_i*z2_i);
    *z3_i=(z1_i*z2_r-z2_i*z1_r)/(z2_r*z2_r+z2_i*z2_i);
}

void par_complex(float z1_r, float z1_i, float *mag, float *ph) // magnitude and phase
{
    *mag=z1_r*z1_r+z1_i*z1_i;
    *ph=atan(z1_i/z1_r)*180/PI;
}

[ 本帖最后由 yuchao130 于 2014-3-14 05:11 编辑 ]

我这样直接发代码是不是不太好啊？

C语言有原生的复数类（关键字_Complex），功能比你这个多，用法比你这个简单

老师规定的条件，很坑爹还用指针，我们是学到哪用到哪