#include<reg52.h>
#include<intrins.h>
#define uchar unsigned char
#define uint unsigned int
uchar temp,num;
uchar code a[]={0x28, 0x7E, 0xA2, 0x62, 0x74, 0x61, 0x21, 0x7A, 0x20, 0x60};

void delay(uint x)
{
    uchar i;
    while(x--)
    {
          for(i=1000;i>0;i--);
    }
}

void main()
{   
    P2=0x00;
    while(1)
    {
        P1=0xfe;
        temp=P1;
        temp=temp&0xf0;
        while(temp!=0xf0)
        {
        //    delay(5);
            temp=P1;
            temp=temp&0xf0;
            while(temp!=0xf0)
            {
                temp=P1;
                switch(temp)
                {
                    case 0xee:num=1;break;
                    case 0xde:num=2;break;
                    case 0xbe:num=3;break;
                    case 0x7e:num=4;break;
                }
                P0=a[num-1];
                while(temp!=0xf0)
                    {
                        temp=P1;
                        temp=temp&0xf0;
                    }
            }
        }
        P1=0xfd;
        temp=P1;
        temp=temp&0xf0;
        while(temp!=0xf0)
        {
            //delay(5);
            temp=P1;
            temp=temp&0xf0;
            while(temp!=0xf0)
            {
                temp=P1;
                switch(temp)
                {
                    case 0xed:num=5;break;
                    case 0xdd:num=6;break;
                    case 0xbd:num=7;break;
                    case 0x7d:num=8;break;
                }
                P0=a[num-1];
                while(temp!=0xf0)
                {
                    temp=P1;
                    temp=temp&0xf0;
                }
            }
        }


    }
}

程序应该没什么问题，你想要按键灵敏一点可以把这个消抖的部分全部去掉，我没得这里可以不用这个，因为里不用考虑按键次数的问题，一个键盘，我想只有在被按时才会有所以谓的抖动，检测到被按下一定是真的被按下，不可能说我没动按键，它自己会有抖动