关于js要调用asp中的结果问题
类似这种，这个循环显示图片和标题是用js调用实现的，<SCRIPT type="text/javascript">
var widths=265;
var heights=150;
var counts=3;
img1=new Image ();img1.src='images/movie/111.jpg';
img2=new Image ();img2.src='images/movie/111.jpg';
img3=new Image ();img3.src='images/movie/111.jpg';
url1=new Image ();url1.src='#';
url2=new Image ();url2.src='#';
url3=new Image ();url3.src='#';
var nn=1;
var key=0;
function change_img()
{if(key==0){key=1;}
else if(document.all)
{document.getElementById("pic").filters[0].Apply();document.getElementById("pic").filters[0].Play(duration=2);}
eval('document.getElementById("pic").src=img'+nn+'.src');
eval('document.getElementById("url").href=url'+nn+'.src');
for (var i=1;i<=counts;i++){document.getElementById("xxjdjj"+i).className='axx';}
document.getElementById("xxjdjj"+nn).className='bxx';
nn++;if(nn>counts){nn=1;}
tt=setTimeout('change_img()',4000);}
function changeimg(n){nn=n;window.clearInterval(tt);change_img();}
document.write('<style>');
document.write('.axx{padding:1px 7px;border-left:#cccccc 1px solid;}');
document.write('a.axx:link,a.axx:visited{text-decoration:none;color:#fff;line-height:12px;font:9px sans-serif;background-color:#666;}');
document.write('a.axx:active,a.axx:hover{text-decoration:none;color:#fff;line-height:12px;font:9px sans-serif;background-color:#999;}');
document.write('.bxx{padding:1px 7px;border-left:#cccccc 1px solid;}');
document.write('a.bxx:link,a.bxx:visited{text-decoration:none;color:#fff;line-height:12px;font:9px sans-serif;background-color:#D34600;}');
document.write('a.bxx:active,a.bxx:hover{text-decoration:none;color:#fff;line-height:12px;font:9px sans-serif;background-color:#D34600;}');
document.write('</style>');
document.write('<div style="width:'+widths+'px;height:'+heights+'px;overflow:hidden;text-overflow:clip;">');
document.write('<div><a id="url"><img id="pic" style="border:0px;filter:progid:dximagetransform.microsoft.wipe(gradientsize=1.0,wipestyle=4, motion=forward)" width='+widths+' height='+heights+' /></a></div>');
document.write('<div style="filter:alpha(style=1,opacity=10,finishOpacity=80);background: #888888;width:100%-2px;text-align:right;top:-12px;position:relative;margin:10px;height:10px;padding:0px;margin:0px;border:0px;">');
for(var i=1;i<counts+1;i++){document.write('<a href="javascript:changeimg('+i+');" id="xxjdjj'+i+'" class="axx" target="_self">'+i+'</a>');}
document.write('</div></div>');
change_img();
</SCRIPT>
显示数据库中图片的问题我已经解决了，关键是标题显示放在哪个地方啊……
[ 本帖最后由 javaxingxing 于 2010-1-31 15:46 编辑 ]
